Web8 jan. 2024 · Best answer Answer is (A) 0 The given line is (x - 3)/1 = (y + 2)/-1 = (z + λ)/-2 Let P be any point on the line, which is given by P = (k + 3, −k −2, −2k – λ) lies on the given plane 2x – 4y + 3z = 2. Therefore, 2 (k + 3) − 4 (−k − 2) + 3 (−2k – λ) = 2 ⇒ 2k + 6 + 4k + 8 – 6k − 3λ = 2 ⇒ 14 – 3λ = 2 ⇒ 3λ = 12 ⇒ λ = 4 WebIf x < 0 then y 1 = x3 and y 2 = −x3, while if x > 0 we have y 1 = x3 and y 2 = x3. So, there is no constant c such that y 1 = cy 2 on the entire real line, and therefore y 1 and y 2 are linearly independent on the real line. (b) - The Wronskian of these two functions is: W(y 1,y 2) = x3 x3 3x 3x x = 3x 4 x − 3x4 x = 0. This does not ...
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WebP(−3 ≤ 3X −4Y ≤ 5). The normal table is attached. Solution: (a) By the independence of X and Y , Cov[X,Y]=0. (b) By independence again, E[X2Y2]=E[X2]E[Y2]. But E[X2] = Var[X]+(E[X])2 = 1+0 = 1, and similarly E[Y2] = 1. We have E[X2Y 2]=1. (c) Note that 3X−4Y is again a normal random variable with mean 0 and variance (−3)2+ 42 =52 ... WebStart typing, then use the up and down arrows to select an option from the list. Create Account Sign in. Explore. Table of contents. 1. ... Solve each system in Exercises 5–18. 2x−4y+3z=17, x+2y−z=0, 4x−y−z=6. Show Answer. Verified Solution. This video solution was recommended by our tutors as helpful for the problem above. fit table to screen html
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Web4 mrt. 2024 · Explanation: We set up the two equations with 'matching' components and then use algebra to reduce the terms to a solution (if there is one). 1) x − 4y = 2 2) x − … WebAlgebra Graph x-2y=4 x − 2y = 4 x - 2 y = 4 Solve for y y. Tap for more steps... y = −2+ x 2 y = - 2 + x 2 Rewrite in slope-intercept form. Tap for more steps... y = 1 2x− 2 y = 1 2 x - 2 Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 1 2 1 2 y-intercept: (0,−2) ( 0, - 2) Web17 mrt. 2024 · However, some functions y are written implicitly as functions of x. So what we do is to treat y as y = y(x) and use chain rule. This means differentiating y w.r.t. y, but as we have to derive w.r.t. x, as per chain rule, we multiply it by dy dx. Hence implicit differentiating 4y2 +2 = 3x2, we get 4 × 2y × dy dx +0 = 3 × 2x fit table to text width latex